The solution to GATE-BT-2017 // Q52

A DNA strand of 25 nm wraps diametrically around the circumference of a spherical histone-octamer once. The radius of the histone-octamer = ____
[Use pi = 3.14]

ANSWER:
Given: 3.90 - 4.10

Answer calculated: 3.95 nm

Steps:

1. 25 nm wraps once = it covers the perimeter of a 'circle that coincides with the sphere's diameter'

Thus, 25 nm = perimeter = 2r(pi) or pi x D,

2. Perimeter is pi x D = 25
Therefore,
    D = 25 / 3.14
    D = 7.9 nm

3. Find the radius from D like a school child :)
because D = 2R

Therefore, R = D/2 = 7.9 nm / 2 = 3.95 nm

R = 3.95 nm.

My answer matches with the answer key, so I think this does well to the question.
If I am wrong, do let me know in the comments below.

You can also let me know what other GATE BT / XL or CSIR - LS you'd like to see me solve!

Byee.

Hakuna Matata

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